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previous-year-question-paper-2025-set-4

SOLUTIONS

2025 BOARD EXAM

CBSE CLASS 10 SCIENCE Board Paper 2025 — Set 4

2025

SCIENCE

CLASS 10

CBSE EXAMINATION SOLVED PAPER-2025 SCIENCE

CBSE EXAMINATION PAPER-2025

SCIENCE

(Solved)

Time allowed : 3 hours

Maximum Marks : 69

General Instructions :

Read the following instructions carefully and follow them :

  1. This question paper contains 32 questions. All questions are compulsory.
  2. This question paper is divided into 5 sections.
  3. Section A – questions number 1 to 1 are case based questions
  4. Section B – questions number 2 to 13 are multiple choice questions
  5. Section C – questions number 14 to 21 are very short answer
  6. Section D – questions number 22 to 28 are short answer
  7. Section E – questions number 29 to 32 are long answer
  8. There is no overall choice given in the question paper. However, an internal choice has been provided in few questions.
  9. Use of calculator is NOT allowed.

Section A

Question 1.

The students in a class took a thick sheet of cardboard and made a small hole in its centre. Sunlight was allowed to fall on this small hole and they obtained a narrow beam of white light. A glass prism was taken and this white light was allowed to fall on one of its faces. The prism was turned slowly until the light that comes out of the opposite face of the prism appeared on the nearby screen. They studied this beautiful band of light and concluded that it is a spectrum of white light.

(1)

List two conditions necessary to observe a rainbow.

[2 Marks]
Answer: To observe a rainbow, two key conditions must be met: firstly, there needs to be sunlight or a source of white light shining in one direction. Secondly, there must be water droplets or some form of moisture in the atmosphere, like after rain, which serves to refract and reflect the light, creating the spectrum of colors visible as a rainbow.
Key Points: Presence of sunlight-Existence of water droplets

(2) What happens to white light in the above case?

[1 Marks]
Answer: In the given experiment, when white light passes through a glass prism, it undergoes a phenomenon known as dispersion. The prism causes the white light to bend at different angles due to the variation in the speed of light in different colors. As a result, the light is separated into its constituent colors, which are red, orange, yellow, green, blue, indigo, and violet. This beautiful band of colors is observed on the screen. This demonstrates that sunlight is not a single color, but rather a mixture of multiple colors that can be identified and visualized through the prism.
Key Points: Dispersion of light, different angles of bending, constituent colors of white light, observation of a spectrum

(3) Give any one more instance in which this type of spectrum is observed.

[1 Marks]
Answer: One more instance where a similar spectrum can be observed is during the formation of a rainbow. When sunlight passes through water droplets in the atmosphere, it refracts and disperses similar to how it does when it passes through a prism. This phenomenon results in the appearance of a rainbow, which displays a beautiful spectrum of colors, similar to the one observed with the prism experiment.
Key Points: rainbow formation-sunlight refraction-water droplets-appearance of spectrum

(4)

Draw a ray diagram to show the formation of a rainbow. Mark on it, points (a), (b) and (c) as given below :

(a) where dispersion of light occurs,

(b) where light gets reflected internally,

(c) where final refraction occurs.

[2 Marks]
Answer: To show the formation of a rainbow through a ray diagram, I will draw a semicircular arc representing a raindrop. First, I will indicate the incoming sunlight as a straight line hitting point (a) on the surface of the droplet where dispersion of light occurs. The different colors of light split at this point due to refraction as light passes into the droplet. I will show the internal reflection at point (b) where the light bounces off the inner surface of the droplet. Lastly, I will depict the emerging light rays exiting the droplet at point (c), where final refraction occurs, spreading out to form a colorful arc of a rainbow in the sky. The diagram illustrates how each color refracts at different angles, creating a spectrum of colors visible as a rainbow.
Key Points: Draw a semicircular raindrop shape; indicate incoming sunlight; mark point (a) for dispersion; mark point (b) for internal reflection; mark point (c) for final refraction; illustrate emerging colored light rays.

Section B

Question 2. The property by virtue of which solid material can be drawn into thin wire is called:
[1 Marks]
  • (A) Malleability
  • (B) Ductility
  • (C) Resistivity
  • (D) Rigidity
Explanation: The correct answer is Ductility. Ductility is the ability of metals to be drawn into thin wires, which is specifically mentioned in the provided context. For example, gold is noted as the most ductile metal, capable of being drawn into long wires.
Question 3.

Select from the following a hydrocarbon having one C–C bond and one C≡C bond:

[1 Marks]
  • (A) Butyne
  • (B) Benzene
  • (C) Cyclohexane
  • (D) Propyne
Explanation: The correct option is Propyne. Propyne has three carbon atoms with one carbon-carbon single bond (C–C) and one carbon-carbon triple bond (C≡C). This satisfies the requirement of having one C–C bond and one C≡C bond, making it an unsaturated hydrocarbon classified as an alkyne. The other options either do not satisfy this criterion or contain only single or double bonds.
Question 4. The essential element taken up from the soil by the plants to synthesize proteins is:
[1 Marks]
  • (A) Iron
  • (B) Nitrogen
  • (C) Phosphorus
  • (D) Magnesium
Explanation: Nitrogen is the correct answer as it is explicitly mentioned in the context that nitrogen is an essential element used in the synthesis of proteins and other compounds. It is absorbed by plants in the form of inorganic nitrates or nitrites, highlighting its crucial role in protein synthesis.
Question 5.

Select TRUE statements about lymph from the following :

A. Lymph vessels carry lymph through the body and finally open into larger arteries.

B. Lymph contains some amount of plasma, proteins and blood cells.

C. Lymph contains some amount of plasma, proteins and red blood cells.

D. Lymph vessels carry lymph through the body and finally open into larger veins.

[1 Marks]
  • (A) C and D
  • (B) A and B
  • (C) A and C
  • (D) B and D
Explanation: The correct statements are B and D. Lymph does contain some amount of plasma, proteins, and blood cells, but it is also noted that it contains less protein compared to blood plasma. Additionally, lymph vessels carry lymph through the body and finally open into larger veins, not arteries, which aligns with the context provided.
Question 6.

Plants like rose and banana have lost the capacity to produce :

[1 Marks]
  • (A) fruits
  • (B) seeds
  • (C) flowers
  • (D) buds
Explanation: The correct answer is 'seeds' because the context clearly states that plants such as rose and jasmine have lost the capacity to produce seeds. This indicates that, unlike many other plants, these specific types cannot reproduce through seeds.
Question 7.

Ina bisexual flower the male gametes are present in the :

[1 Marks]
  • (A) anther
  • (B) filament
  • (C) ovary
  • (D) stigma
Explanation: The correct answer is 'anther'. The anther is the part of the stamen that is responsible for producing pollen grains, which contain the male gametes. The context mentions that the stamen is the male reproductive part and produces pollen grains, confirming that the anther is where the male gametes are located.
Question 8.

To get an image of magnification —1 on a screen using a lens of focal length 20 cm, the object distance must be :

[1 Marks]
  • (A) Less than 20 cm
  • (B) 40 cm
  • (C) 80 cm
  • (D) 30 cm
Explanation: The correct option is 40 cm. According to the lens formula, for an image with magnification of -1 (inverted image), the object distance should be equal to twice the focal length of the lens. With a focal length of 20 cm, the object distance is calculated as u = -2f = -2(20) = -40 cm (the negative sign indicates that the object is on the same side as the incoming light).
Question 9.

An optical device ‘X’ is placed obliquely in the path of a narrow parallel beam of light. If the emergent beam gets displaced laterally, the device ‘X’ is:

[1 Marks]
  • (A) glass prism
  • (B) plane mirror
  • (C) convex lens
  • (D) glass slab
Explanation: The correct option is 'glass slab'. When light passes through a glass slab at an angle, it undergoes refraction but the emergent ray remains parallel to the incident ray, and there is a lateral displacement. This behavior matches the context provided, which describes how light interacts with a slab.
Question 10.

An electric bulb is rated 220 V; 11W. The resistance of its filament when it glows with a power supply of 220 V is :

[1 Marks]
  • (A) 4400 Ω
  • (B) 20 Ω
  • (C) 440 Ω
  • (D) 400 Ω
Explanation: To find the resistance (R) of the bulb, we can use the formula P = V^2 / R, where P is the power (11 W) and V is the voltage (220 V). Rearranging this gives us R = V^2 / P = (220^2) / 11 = 48400 / 11 = 4400 Ω. Thus, the correct answer is 4400 Ω.
Question 11.

The minimum number of identical bulbs of rating 4V; 6W, that can work safely with desired brightness, when connected in series with a 240 V mains supply is :

[1 Marks]
  • (A) 20
  • (B) 40
  • (C) 60
  • (D) 80
Explanation: To find the minimum number of bulbs, we first need to calculate the total resistance required to allow the bulbs to work correctly with the provided voltage. The power rating formula is P = V^2/R, which can be rearranged to R = V^2/P. For one bulb, R = (4^2) / 6 = 2.67 ohms. Since they are connected in series, the total resistance R_total = n * resistance of one bulb. Thus, V_total = I * R_total, converted into total voltage of 240V, solving gives n = 60. Therefore, the correct answer is 60.
Question 12.

In the food chains given below. Select the most efficient food chain in terms of energy :

[1 Marks]
  • (A) Phytoplankton → Zooplankton → Small Fish → Big Fish
  • (B) Plants → Deer → Lion
  • (C) Plants → Man
  • (D) Grass → Grasshopper → Frog → Snake
Explanation:

The most efficient food chain in terms of energy is 'Phytoplankton → Zooplankton → Small Fish → Big Fish'. This chain consists of fewer trophic levels, which generally allows for a higher retention of energy at each level. According to the context, with each step in the food chain, energy is lost significantly, so shorter chains retain more energy. The other options contain more steps, which leads to higher energy loss.

Question 13.

Which one of the following gets biomagnified at different levels in a food chain ?

[1 Marks]
  • (A) Manure
  • (B) DDT
  • (C) Carbon monoxide
  • (D) CFC’s
Explanation: DDT is correct because it is a chemical that accumulates in the bodies of organisms at each trophic level, leading to higher concentrations in top predators, including humans, due to biological magnification. This is reflected in the context, which discusses how non-degradable chemicals like pesticides enter the food chain and are progressively accumulated.

Section C

Question 14.

Define oxidation. Identify and name the substance oxidized in the following reaction:

CuO + H₂ → Cu + H₂O

[2 Marks]
Answer: (a) Oxidation means the process where a substance loses electrons or gains oxygen during a chemical reaction.
(b) In the reaction CuO + H₂ → Cu + H₂O, hydrogen (H₂) is oxidized because it gains oxygen to form water (H₂O). So, the substance oxidized is hydrogen (H₂).
Question 15.

Show the formation of magnesium chloride by electron transfer. Write the name of the cation and anion present in the compound formed. (Atomic Number of Mg = 12, Cl = 17)

[2 Marks]
Answer: Formation of magnesium chloride:
Magnesium atom (Mg) has 2 electrons in its outermost shell and chlorine atom (Cl) has 7 electrons in its outermost shell. Magnesium transfers its 2 electrons, one to each chlorine atom. This forms Mg2+ ion and two Cl- ions.
Equation: Mg → Mg2+ + 2e-
2Cl + 2e- → 2Cl-
These oppositely charged ions (Mg2+ and Cl-) attract each other and form an ionic bond, resulting in magnesium chloride with formula MgCl2.
Cation: Magnesium ion (Mg2+)
Anion: Chloride ion (Cl-)
Question 16. ‘Plants use a variety of techniques to get rid of waste material.’ Justify this statement giving any four ways.
[2 Marks]
Answer: Plants employ several methods to eliminate waste materials. Firstly, they lose excess water through transpiration, which is crucial in regulating their internal moisture levels. Secondly, dead cell tissues, like the bark, shed serve as another waste elimination strategy. Additionally, many waste products are stored in cellular vacuoles within the plant cells, allowing for safe storage and later disposal. Lastly, oxygen produced during photosynthesis is expelled as a waste product, representing another important form of waste excretion in plants.
Question 17.

Explain with the help of a flow chart that in human beings father is responsible for the sex (male or female) of the child.

[2 Marks]
Answer: Sex determination in humans:
1. Humans have 23 pairs of chromosomes including one pair of sex chromosomes.
2. Mothers have two X chromosomes (XX), so eggs always carry X.
3. Fathers have one X and one Y chromosome (XY), so sperms carry either X or Y.
4. During fertilization:
    - If sperm carrying X fertilizes the egg (X), the child will be female (XX).
    - If sperm carrying Y fertilizes the egg (X), the child will be male (XY).
5. Therefore, the father determines the sex of the child by contributing either X or Y chromosome.
Flow chart:
Father (XY) -- produces sperm with X or Y --> Egg (X) from Mother
--X sperm + X egg = Female (XX)
--Y sperm + X egg = Male (XY)
Question 18. Draw a ray diagram to show the refraction of light passing through an equilateral glass prism. Mark the angle through which the emergent ray bends from the direction of the incident ray and also name it.
[2 Marks]
Answer: When light passes through an equilateral glass prism, it refracts twice. First, it bends towards the normal when entering the prism (from air to glass) at surface AB. Inside the prism, it travels straight. At surface AC, it bends away from the normal when emerging from glass to air. The emergent ray bends from the original incident ray direction by an angle called the angle of deviation (D). This angle D is the measure of how much the ray is deviated due to refraction through the prism.
Question 19. Name the type of lens required by persons for the correction of vision called presbyopia. Write the structure of the lenses commonly used for the correction of this defect, giving reason for such designs.
[2 Marks]
Answer: The type of lens required to correct presbyopia is a bifocal lens. Such lenses have two parts: the upper portion is a concave or sometimes plano lens for distance vision, and the lower portion is a convex lens for near vision. This design helps persons with presbyopia to see distant and near objects clearly because the eye's lens loses flexibility with age, making it difficult to focus on close objects. The convex lower part assists in focusing light from near objects on the retina.
Question 20. What are magnetic field lines? List two important properties of magnetic field lines.
[2 Marks]
Answer: Magnetic field lines are imaginary lines used to represent the magnetic field around a magnet. They show the direction and strength of the magnetic field. The lines come out from the North pole and go into the South pole of the magnet.
Two important properties of magnetic field lines are:
1. Magnetic field lines never cross each other.
2. The tangent to a magnetic field line at any point gives the direction of the magnetic field at that point.
Question 21.

How is zinc extracted from its ore? Name the processes involved in the extraction and write chemical equations for the reactions that occur during these processes.

[2 Marks]
Answer: Extraction of Zinc from its Ore:
Zinc is mainly extracted from its ore zinc blende (ZnS) by the following processes:
(a) Roasting: The zinc sulphide ore is heated in the presence of excess air to convert it into zinc oxide. This process is called roasting.
Chemical equation:
2ZnS (s) + 3O2 (g) --Heat--> 2ZnO (s) + 2SO2 (g)
(b) Reduction of Zinc Oxide: The zinc oxide obtained is then reduced to zinc metal by heating with carbon (coke). This process is called reduction.
Chemical equation:
ZnO (s) + C (s) --Heat--> Zn (s) + CO (g)
Thus zinc is extracted from its ore by roasting followed by reduction.

Section D

Question 22.

Why do we balance a chemical equation? Name and state the law that suggests the balancing of a chemical equation? Balance the following chemical equation:

Zn + H₃PO₄ → Zn₃(PO₄)₂ + H₂

[3 Marks]
Answer: (a) We balance a chemical equation to follow the law of conservation of mass, which states that matter can neither be created nor destroyed in a chemical reaction. This ensures that the number of atoms of each element on the reactant side is equal to that on the product side.
(b) The law that suggests balancing is the Law of Conservation of Mass. It states that mass of reactants is always equal to the mass of products in a chemical reaction.
(c) To balance Zn + H₃PO₄ → Zn₃(PO₄)₂ + H₂:
Step 1: Count atoms on both sides:
Zn: Reactant=1, Product=3
H: Reactant=3, Product=2
P: Reactant=1, Product=2
O: Reactant=4, Product=8
Step 2: Balance Zn atoms by putting 3 before Zn:
3Zn + H₃PO₄ → Zn₃(PO₄)₂ + H₂
Step 3: Balance PO₄ groups by putting 2 before H₃PO₄:
3Zn + 2H₃PO₄ → Zn₃(PO₄)₂ + H₂
Step 4: Balance H atoms: Reactants= 2*3=6, Products= H₂ so put 3 before H₂:
3Zn + 2H₃PO₄ → Zn₃(PO₄)₂ + 3H₂
All atoms are balanced now. This is the balanced equation.
Question 23. Define a precipitation reaction. Give its example and express the reaction that occurs in the form of a balanced chemical equation.
[3 Marks]
Answer: Definition: A precipitation reaction is a type of chemical reaction in which two solutions react to form an insoluble solid called a precipitate.
Example: When silver nitrate solution (AgNO3) is mixed with sodium chloride solution (NaCl), a white precipitate of silver chloride (AgCl) is formed.
Reaction: AgNO3(aq) + NaCl(aq) → AgCl(s) + NaNO3(aq)
Here, AgCl is the precipitate which is insoluble in water and appears as a white solid.
This reaction is an example of a double displacement reaction followed by the formation of a precipitate, hence a precipitation reaction.
Question 24.

Design an activity to show that metals are good conductors of heat and have high melting points.

[3 Marks]
Answer: To show that metals are good conductors of heat and have high melting points, follow this activity: (a) Take a thin metal wire made of copper or aluminium and clamp it firmly on a stand. (b) Fix a small pin to the free end of the wire using wax. (c) Heat the wire near the clamp using a spirit lamp, candle, or burner.
Observation: After some time, the heat travels through the wire and melts the wax, causing the pin to fall off. This shows that heat is conducted through the metal wire.
Note: The metal wire does not melt even after heating for long, which shows that metals have high melting points.
This activity proves that metals are good conductors of heat and have high melting points as they conduct heat rapidly and do not melt easily.
Question 25.

The digestion of food in human alimentary canal is a complex process. State the enzyme/salt present in the following and mention their function in the process of digestion :

(i) Saliva

(ii) Bile Juice

(iii) Pancreatic Juice

[3 Marks]
Answer: (i) Saliva: Saliva contains the enzyme salivary amylase which starts the digestion of starch into maltose in the mouth. It also moistens the food to help in easy swallowing.
(ii) Bile Juice: Bile juice contains bile salts which emulsify fats, breaking large fat globules into smaller droplets. This increases the surface area for the action of lipase enzymes, aiding fat digestion. Bile juice is produced by the liver and stored in the gall bladder.
(iii) Pancreatic Juice: Pancreatic juice contains several digestive enzymes such as pancreatic amylase (breaks down starch into maltose), pancreatic lipase (breaks down fats into glycerol and fatty acids), and proteases like trypsin (break down proteins into smaller peptides). It is secreted by the pancreas into the small intestine where it helps in the digestion of carbohydrates, proteins, and fats.
Question 26.

State two limitations of electrical impulses in multicellular organisms. Why is chemical communication better than electrical impulses as a means of communication between cells in multicellular organisms?

[3 Marks]
Answer: (a) Two limitations of electrical impulses in multicellular organisms are:
1. Electrical impulses can only travel through cells that are connected by nervous tissue, so they cannot reach every cell in the body.
2. After sending an electrical impulse, a cell needs time to reset before it can send another impulse, so continuous and rapid communication is not possible.
(b) Chemical communication is better than electrical impulses because chemicals released by cells can diffuse to many nearby cells, not just cells connected by nerves. This allows wider and more flexible communication. Also, chemicals can cause longer-lasting effects and regulate several processes at once, which electrical impulses cannot do efficiently.
Question 27.

If we want to obtain a virtual and magnified image of an object by using a concave mirror of focal length 18 cm, where should the object be placed? Use mirror formula to determine the object distance for an image of magnification +2 produced by this mirror to justify your answer.

[3 Marks]
Answer: To obtain a virtual and magnified image using a concave mirror, the object must be placed between the focal point (F) and the mirror surface. Given:
Focal length, f = -18 cm (negative for concave mirror)
Magnification, m = +2 (positive sign indicates virtual and magnified image)
Magnification formula: m = -v / u
So, v = -m * u = -2u
Using mirror formula: 1/f = 1/v + 1/u
Substitute values: 1/(-18) = 1/(-2u) + 1/u
1/(-18) = (-1/2u) + 1/u = ( -1/2u + 2/2u ) = 1/(2u)
Therefore, 1/(-18) = 1/(2u) => 2u = -18 => u = -9 cm
Since object distance u is negative, the object is 9 cm in front of the mirror.
This position is between the focal point (18 cm) and the mirror (0 cm).
Hence, placing the object 9 cm in front of the concave mirror of focal length 18 cm will produce a virtual and magnified image with magnification +2.
Question 28.

The electrical resistivity of three materials A, B and C at 20°C is given below:

(i) Classify these materials as conductor, alloy and insulator.

(ii) Give one example of each of these materials and state one use of each material in the design of an electrical appliance say an electric stove or an electric iron.

[3 Marks]
Answer: (i) Material A is a conductor because it has very low resistivity, allowing electric current to flow easily. Material B is an alloy because it has higher resistivity than pure conductors and is used in heating elements due to its resistance properties. Material C is an insulator as it has very high resistivity, preventing the flow of electric current.
(ii) Examples and uses:
Conductor - Copper: Used in electric iron for wiring because it allows efficient current flow.
Alloy - Nichrome: Used in the heating element of electric stove or electric iron because it resists oxidation at high temperatures and produces heat when current passes.
Insulator - Bakelite: Used as the handle of electric stove or iron to prevent electric shock because it does not conduct electricity.

Section E

Question 29.

(i) What is regeneration? Give one example of an organism that shows this process and one organism that does not. Why does regeneration not occur in the latter?

(ii) Water in a pond appears dark green and contains filamentous structures. Name these structures and the method by which they reproduce. Explain the process.

[5 Marks]
Answer: (i) Regeneration is the process by which some organisms can regrow lost or damaged body parts. This happens because special cells in their body divide and develop into the missing parts, helping the organism to recover completely. For example, Planaria can regenerate their body parts if cut into pieces; each piece can grow into a new complete organism. On the other hand, organisms like earthworms do not show this kind of regeneration fully. This is because they lack the special stem cells or organised system required for regrowth of complex structures and their cells have limited ability to multiply and differentiate into all types of tissues needed.

(ii) The dark green filamentous structures in pond water are algae, specifically filamentous algae such as Spirogyra. These reproduce by a method called conjugation. In conjugation, two filaments of algae come close, and a tube forms between adjacent cells of the two filaments. The contents of one cell (male gamete) move through this tube to fuse with the contents of the other cell (female gamete). This fusion results in the formation of a zygote, which develops into a new filament. This process helps in sexual reproduction and increases genetic variation.
Question 30.

(i)Name the part performing following functions in human male reproductive system :

(a) Carries sperm

(b) Production of male gametes

(c) Whose secretion makes the transport of sperms easier

(d) Provide suitable temperature for sperm formation

(ii) Write any two characteristics of sperms.

(iii) What are surgical contraceptive methods? Give the side effect caused by this procedure.

[5 Marks]
Answer: (i) Parts performing the functions in the male reproductive system:
(a) The part that carries sperm is called the vas deferens or sperm duct.
(b) The production of male gametes or sperms takes place in the testes.
(c) The secretion that makes the transport of sperms easier is produced by the prostate gland and seminal vesicles. These secretions form the semen which nourishes and helps sperms to move.
(d) The part that provides a suitable temperature for sperm formation is the scrotum. It keeps the testes at a temperature slightly lower than the body temperature which is important for healthy sperm production.

(ii) Two characteristics of sperms:
1. Sperms have a tail called flagellum that helps them to swim towards the ovum.
2. Sperms are very small and have a head containing genetic material (DNA) to fertilize the female egg.

(iii) Surgical contraceptive methods:
Surgical methods are permanent methods of birth control used to prevent the production or transport of sperms.
In males, this method is called vasectomy, where the vas deferens is cut and tied to stop sperm from entering semen.
Side effect: The main side effect is that vasectomy is permanent and difficult to reverse. Some men may also experience pain or swelling after the surgery.
Question 31.

(i) Draw the pattern of the magnetic field lines for the two parallel straight conductors carrying current of same magnitude ‘I’ in opposite directions as shown. Show the direction of magnetic field at a point O which is equidistant from the two conductors. (Consider that the conductors are inserted normal to the plane of a rectangular cardboard.)

(ii) In our houses we receive A.C. electric power of 220 V. In electric iron or electric heater cables having three wires with insulation of three different colours — red, black and green are used to draw current from the mains.

(a) What are these three different wires called? Name them colourwise.

(b) What is the potential difference between the red wire and the black wire?

(c) What is the role of the wire with green insulation in case of accidental leakage of electric current to the metallic body of an electrical appliance?

[5 Marks]
Answer: (i) The magnetic field lines around two parallel conductors carrying current in opposite directions form concentric circles around each conductor. Since the currents are opposite, at point O which is equidistant from both conductors, the magnetic fields due to each wire add up in the same direction. The direction of the magnetic field around each wire is given by the right-hand thumb rule: point your thumb in the direction of current, your curled fingers show the direction of magnetic field. The magnetic field lines between the two wires are in the same direction at point O, so the net magnetic field at O is the vector sum of both fields.
(ii) (a) The three wires are called live wire (red), neutral wire (black), and earth wire (green).
(ii) (b) The potential difference between the red wire (live) and the black wire (neutral) is 220 V.
(ii) (c) The green wire is the earth wire. Its role is to safely conduct any leakage current from the metallic body of the appliance to the ground, preventing electric shocks to the user and protecting the appliance from damage.
Question 32.

(i) By using the given experimental set-up. How can it be shown that:

(a) a force is exerted on the current-carrying B conductor AB when it is At placed in a magnetic field.

(b) the direction of force can be reversed in two ways.

(ii) When will the magnitude of the force be highest?

(iii) State Fleming’s left hand rule.

[5 Marks]
Answer: (i) (a) When a current-carrying conductor AB is placed between the poles of a magnet, the magnetic field interacts with the moving charges in the conductor, exerting a force on it. This force can be observed as a movement or deflection of the conductor. This shows that a force is exerted on the conductor AB in the magnetic field.
(b) The direction of force on the current-carrying conductor can be reversed in two ways:
1. By reversing the direction of the current in the conductor.
2. By reversing the direction of the magnetic field.
In both cases, the direction of force changes as predicted by Fleming's left-hand rule.
(ii) The magnitude of the force on the conductor is highest when the conductor is placed perpendicular to the magnetic field and the current is also perpendicular to the magnetic field. This means the conductor, current and magnetic field are mutually perpendicular.
(iii) Fleming’s left hand rule states that if you stretch the thumb, forefinger, and middle finger of your left hand such that they are mutually perpendicular to each other:
- The Forefinger points in the direction of the magnetic Field (from North to South).
- The seCond finger points in the direction of the Current (from positive to negative).
- The thuMb points in the direction of the Motion or the force acting on the conductor.
This rule helps to find the direction of force on a current-carrying conductor placed in a magnetic field.

Paper Details

CBSE Board Exam 2025

Class

CLASS 10

Subject

SCIENCE

Year

2025

Set

Set 4

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2024 Set-1

2024 Set-2

2024 Set-3

2024 Set-4

2024 Set-5

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2025 Set-2

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