CLASS 9 . MATHEMATICS . GANITA MANJARI . EXPLORING ALGEBRAIC-IDENTITIES
Chapter 4 : Exploring Algebraic Identities
Ch 4
MATHEMATICS
CLASS 9
Patterns in Consecutive Square Numbers
This section explores a pattern observed in three consecutive square numbers. Consider three consecutive integers n - 1, n, and n + 1 and their squares (n - 1)2, n2, and (n + 1)2.
Formula Derivation
Sum the smallest and largest squares and subtract twice the middle square:
(n - 1)2 + (n + 1)2 - 2n2
Expanding each term:
(n2 - 2n + 1) + (n2 + 2n + 1) - 2n2 = n2 - 2n + 1 + n2 + 2n + 1 - 2n2
Simplify:
= (n2 + n2 - 2n2) + (-2n + 2n) + (1 + 1) = 0 + 0 + 2 = 2
Thus, the result is always 2 for any integer n.
Worked Illustration
- For n = 2, squares are 1, 4, 9. Calculation: 1 + 9 - 2 × 4 = 10 - 8 = 2.
- For n = 4, squares are 9, 16, 25. Calculation: 9 + 25 - 2 × 16 = 34 - 32 = 2.
- For n = 6, squares are 25, 36, 49. Calculation: 25 + 49 - 2 × 36 = 74 - 72 = 2.
Practice Set
- Level 1: Verify the pattern for n = 3, 5, 7.
- Level 2: Prove the pattern for four consecutive squares (n - 1)2, n2, (n + 1)2, (n + 2)2.
- Level 3: Explore if a similar pattern exists for cubes of three consecutive numbers.
Answer Key
- Level 1: The result is always 2.
- Level 2: Requires algebraic expansion and simplification.
- Level 3: Investigation and proof required.
Quick Reference
(n - 1)2 + (n + 1)2 - 2n2 = 2
Glossary
- Consecutive numbers: Numbers that follow each other in order.
- Square of a number: The product of the number with itself.
Visualising Algebraic Identities
This section uses geometric models to understand algebraic identities, particularly squares and rectangles representing terms.
Concept Explanation
Consider two line segments of lengths a and b. Construct a square of side a + b and partition it into smaller squares and rectangles.
Formula Derivation
The area of the large square is (a + b)2. Partitioning it gives:
- Square of side a with area a2.
- Square of side b with area b2.
- Two rectangles each with area ab.
Summing these areas:
(a + b)2 = a2 + 2ab + b2
Worked Illustration
- Example: Expand (5x + 2y)2 = 25x2 + 20xy + 4y2.
- Calculate 432 using the identity: (40 + 3)2 = 1600 + 240 + 9 = 1849.
Practice Set
- Level 1: Expand (3a + 4b)2.
- Level 2: Calculate 572 using the identity.
- Level 3: Factor expressions like x2 + 6x + 9 using the identity.
Answer Key
- Level 1: 9a2 + 24ab + 16b2.
- Level 2: 572 = (50 + 7)2 = 2500 + 700 + 49 = 3249.
- Level 3: x2 + 6x + 9 = (x + 3)2.
Quick Reference
(a + b)2 = a2 + 2ab + b2
Glossary
- Algebraic identity: An equation true for all values of variables.
- Binomial: An algebraic expression with two terms.
Expansion and Factorisation of Algebraic Expressions
This section covers the use of algebraic identities to expand and factor expressions.
Concept Explanation
Using identities like (a + b)2 = a2 + 2ab + b2 and (a - b)2 = a2 - 2ab + b2 to expand expressions and factor quadratic expressions.
Formula Derivation
Example of factorisation:
x2 + 4x + 4 = (x + 2)2
By comparing with a2 + 2ab + b2, where a = x and b = 2.
Worked Illustrations
- Factor 36x2 + 12x + 1 = (6x + 1)2.
- Factor 50p2 + 60pq + 18q2 = 2(5p + 3q)2.
Practice Set
- Level 1: Factor x2 + 7x + 12.
- Level 2: Factor x2 - 5x + 6.
- Level 3: Factor 4x2 + 12x + 9.
Answer Key
- Level 1: (x + 3)(x + 4).
- Level 2: (x - 2)(x - 3).
- Level 3: (2x + 3)2.
Quick Reference
x2 + (a + b)x + ab = (x + a)(x + b)
Glossary
- Factorisation: Expressing an expression as a product of simpler expressions.
- Quadratic expression: Polynomial of degree 2.
Cube of a Binomial
This section introduces the identity for the cube of a binomial and its geometric visualization.
Formula Derivation
Using distributive property:
(a + b)3 = (a + b)(a + b)2 = (a + b)(a2 + 2ab + b2) = a3 + 3a2b + 3ab2 + b3
Similarly,
(a - b)3 = a3 - 3a2b + 3ab2 - b3
Worked Illustration
- Find the side of a cube with volume p3 + 6p2q + 12pq2 + 8q3 by comparing with (a + b)3.
- Express 8n3 - 60n2m + 150nm2 - 125m3 as (a - b)3.
Practice Set
- Level 1: Expand (x + 2)3.
- Level 2: Factor 27a3 + 64b3.
- Level 3: Factor 125x3 - 216y3.
Answer Key
- Level 1: x3 + 6x2 + 12x + 8.
- Level 2: (3a + 4b)3.
- Level 3: (5x - 6y)3.
Quick Reference
(a + b)3 = a3 + 3a2b + 3ab2 + b3
(a - b)3 = a3 - 3a2b + 3ab2 - b3
Glossary
- Binomial cube: Cube of a binomial expression.
- Cuboid: A three-dimensional rectangular box.
Algebraic Identities Involving Three Variables
This section explores identities involving three variables such as (a + b + c)2 and the factorisation of sums and differences of cubes.
Formula Derivation
For three variables a, b, c,
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
Also,
(x + y + z)(x2 + y2 + z2 - xy - yz - zx) = x3 + y3 + z3 - 3xyz
Worked Illustration
- Calculate the sum of cubes of three numbers given their sum, product, and sum of squares.
Practice Set
- Level 1: Expand (x + y + z)2.
- Level 2: Verify the identity for specific values of x, y, z.
- Level 3: Use the identity to solve problems involving sums and products of three variables.
Answer Key
- Level 1: x2 + y2 + z2 + 2xy + 2yz + 2zx.
- Level 2: Verification by substitution.
- Level 3: Application of the identity to find unknown sums.
Quick Reference
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
(x + y + z)(x2 + y2 + z2 - xy - yz - zx) = x3 + y3 + z3 - 3xyz
Glossary
- Sum of cubes: The sum of the cubes of variables.
- Symmetric expression: Expression unchanged by permutation of variables.
Simplification of Rational Algebraic Expressions
This section explains how to simplify rational expressions by factorisation and cancelling common factors.
Concept Explanation
Given a rational expression P(x)/Q(x), simplify by factoring numerator and denominator and cancelling common factors where Q(x) not equal to 0.
Worked Illustration
- Simplify (x2 - 7x + 12)/(5x2 + 5x - 100):
- Factor numerator: x2 - 7x + 12 = (x - 3)(x - 4).
- Factor denominator: 5x2 + 5x - 100 = 5(x2 + x - 20) = 5(x - 4)(x + 5).
- Cancel common factor x - 4 (assuming x not equal to 4):
- Result: (x - 3)/5(x + 5).
Practice Set
- Level 1: Simplify (36s2 - 12st + t2)/(t2 + 2ts - 48s2).
- Level 2: Simplify (x2 + 5x + 6)/(x2 - 4).
- Level 3: Simplify (4x2 - 9)/(2x2 + 7x + 3).
Answer Key
- Level 1: ((6s - t)2)/((t - 6s)(t + 8s)).
- Level 2: ((x + 2)(x + 3))/((x - 2)(x + 2)) = (x + 3)/(x - 2).
- Level 3: Factor and simplify accordingly.
Quick Reference
Simplify rational expressions by factoring numerator and denominator and cancelling common factors.
Glossary
- Rational expression: Ratio of two polynomials.
- Factor: Expression multiplied to get another expression.