CLASS 6 . MATHEMATICS . GANITA PRAKASH . PERIMETER AND-AREA
Chapter 6 : Perimeter And Area
Ch 6
MATHEMATICS
CLASS 6
Fundamental Facts
Perimeter is the total length around a closed figure when it is expanded into a linear form. It is measured in units such as centimetres (cm), meters (m), inches (in), or feet (ft).
The perimeter of a regular polygon (a polygon with all sides and angles equal) is calculated as:
\[ \text{Perimeter} = \text{Number of sides} \times \text{Length of one side} \]
For a quadrilateral, the perimeter is the sum of the lengths of all four sides.
Units of perimeter correspond to the units of the sides measured.
Introduction
Perimeter: The distance covered along the boundary of a closed figure when you go around it once. It is the length of the boundary.
A regular polygon is a closed figure with all sides and angles equal.
Formulas for perimeter of common shapes:
- Rectangle: \( P = 2 \times (l + b) \), where \( l \) is length and \( b \) is breadth.
- Square: \( P = 4 \times s \), where \( s \) is the side length.
- Equilateral triangle: \( P = 3 \times s \), where \( s \) is the side length.
Area: The amount of surface enclosed by a closed figure.
Formulas for area of common shapes:
- Rectangle: \( A = l \times b \)
- Square: \( A = s \times s = s^2 \)
Perimeter
Perimeter is the total distance around the boundary of a closed figure.
Applications of perimeter include:
- Fencing a field.
- Building a compound wall around a house.
- Preparing a sports track.
Perimeter of a Rectangle
Sum of all sides:
\[ P = l + b + l + b = 2(l + b) \]
Perimeter of Regular Shapes
Regular polygons have all sides and angles equal.
Examples: Square, equilateral triangle, regular pentagon.
Formulas:
- Square: \( P = 4 \times s \)
- Equilateral triangle: \( P = 3 \times s \)
- Regular pentagon: \( P = 5 \times s \)
Example 1
Problem: Akshi wants to put lace all around a rectangular table cloth that is 3 m long and 2 m wide. Find the length of the lace required.
Solution:
Given:
- Length \( l = 3 \) m
- Breadth \( b = 2 \) m
Length of lace required = Perimeter of the table cloth
\[ P = 2(l + b) = 2(3 + 2) = 2 \times 5 = 10 \text{ m} \]
Therefore, 10 meters of lace is required.
Area
Area is the amount of surface enclosed by a closed figure.
To estimate area by counting squares on grid paper, use these conventions:
- Ignore portions less than half a square.
- Count portions more than half a square as one full square.
- If exactly half a square, count as \( \frac{1}{2} \) square unit.
Area of a Rectangle
Formula:
\[ A = l \times b \]
Area of a Square
Formula:
\[ A = s \times s = s^2 \]
Keywords
- Perimeter: Distance covered along the boundary of a closed figure.
- Area: Amount of surface enclosed by a closed figure.
Example 2
Problem: A floor is 5 m long and 4 m wide. A square carpet of side 3 m is laid on the floor. Find the area of the floor that is not carpeted.
Solution:
Floor dimensions:
- Length \( l = 5 \) m
- Width \( w = 4 \) m
Area of floor:
\[ A_{floor} = l \times w = 5 \times 4 = 20 \text{ m}^2 \]
Carpet side length \( s = 3 \) m
Area of carpet:
\[ A_{carpet} = s^2 = 3 \times 3 = 9 \text{ m}^2 \]
Area of floor not carpeted:
\[ A_{not\ carpeted} = A_{floor} - A_{carpet} = 20 - 9 = 11 \text{ m}^2 \]
Practice Set
Level 1 – Easy
- Find the perimeter of a square with side 6 cm.
- Calculate the area of a rectangle with length 8 m and breadth 3 m.
- Find the perimeter of an equilateral triangle with side 5 cm.
Level 2 – Moderate
- A rectangular garden is 15 m long and 10 m wide. Find the length of the fence required to surround the garden.
- A square room has side 12 m. Find the area of the room.
- Find the area of a rectangular field measuring 25 m by 18 m.
Level 3 – Challenging
- A rectangular plot is 40 m long and 30 m wide. A path 2 m wide is constructed all around inside the plot. Find the area of the path.
- A square park has a perimeter of 200 m. Find its area.
- A triangular field is equilateral with side 20 m. Find its perimeter and area.
Answer Key
Level 1 – Easy
- Perimeter of square = \(4 \times 6 = 24 \text{ cm}\)
- Area of rectangle = \(8 \times 3 = 24 \text{ m}^2\)
- Perimeter of equilateral triangle = \(3 \times 5 = 15 \text{ cm}\)
Level 2 – Moderate
- Fence length = Perimeter of garden = \(2(15 + 10) = 2 \times 25 = 50 \text{ m}\)
- Area of room = \(12 \times 12 = 144 \text{ m}^2\)
- Area of field = \(25 \times 18 = 450 \text{ m}^2\)
Level 3 – Challenging
- Area of path:
- Outer area = \(40 \times 30 = 1200 \text{ m}^2\)
- Inner dimensions = \(40 - 2 \times 2 = 36 \) m and \(30 - 2 \times 2 = 26 \) m
- Inner area = \(36 \times 26 = 936 \text{ m}^2\)
- Area of path = Outer area - Inner area = \(1200 - 936 = 264 \text{ m}^2\)
- Square park side = \(\frac{200}{4} = 50 \text{ m}\), area = \(50^2 = 2500 \text{ m}^2\)
- Equilateral triangle perimeter = \(3 \times 20 = 60 \text{ m}\)
- Area of equilateral triangle = \(\frac{\sqrt{3}}{4} s^2 = \frac{\sqrt{3}}{4} \times 20^2 = 100\sqrt{3} \approx 173.21 \text{ m}^2\)
Quick Reference
| Shape | Perimeter | Area |
|---|---|---|
| Rectangle | \(2(l + b)\) | \(l \times b\) |
| Square | \(4s\) | \(s^2\) |
| Equilateral Triangle | \(3s\) | \(\frac{\sqrt{3}}{4} s^2\) |
| Regular Pentagon | \(5s\) | Not covered |
Glossary
- Perimeter: The total length around the boundary of a closed figure.
- Area: The measure of the surface enclosed within a closed figure.
- Regular Polygon: A polygon with all sides and all angles equal.
- Equilateral Triangle: A triangle with all three sides equal.
- Square: A regular quadrilateral with four equal sides and four right angles.
- Rectangle: A quadrilateral with opposite sides equal and four right angles.