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previous-year-question-paper-2024-set-4

QUESTION PAPER

2024 BOARD EXAM

CBSE CLASS 12-PCM CHEMISTRY Board Paper 2024 — Set 4

2024

CHEMISTRY

CLASS 12-PCM

CBSE EXAMINATION PAPER-2024 CHEMISTRY

CBSE EXAMINATION PAPER-2024

CHEMISTRY

(Solved)

Time allowed : 3 hours

Maximum Marks : 12

General Instructions :

Read the following instructions carefully and follow them :

  1. This question paper contains 16 questions. All questions are compulsory.
  2. This question paper is divided into 3 sections.
  3. Section A – questions number 1 to 3 are case based questions
  4. Section B – questions number 4 to 15 are multiple choice questions
  5. Section C – questions number 16 to 16 are very short answer
  6. There is no overall choice given in the question paper. However, an internal choice has been provided in few questions.
  7. Use of calculator is NOT allowed.

Section A

Question 1. The nature of bonding, structure of the coordination compound can be explained to some extent by valence bond theory. The central metal atom/ion makes available a number of vacant orbitals equal to its coordination number. The appropriate atomic orbitals (s, p and d) of the metal hybridise to give a set of equivalent orbitals of definite geometry such as square planar, tetrahedral, octahedral and so on. A strong covalent bond is formed only when the orbitals overlap to the maximum extent. The d-orbitals involved in the hybridisation may be either inner d-orbitals i.e. (n-1)d or outer d-orbitals i.e. nd. The complexes formed are called inner orbital complex (low spin complex) and outer orbital complex (high spin complex) respectively. Further, the complexes can be paramagnetic or diamagnetic in nature. The drawbacks of this theory are that this involves number of assumptions and also does not explain the colour of the complex.
Question 2.
Question 3.

20.         The nature of bonding, structure of the coordination compound can be explained to some extent by valence bond theory. The central metal atom/ion makes available a number of vacant orbitals equal to its coordination number. The appropriate atomic orbitals (s, p and d) of the metal hybridise to give a set of equivalent orbitals of definite geometry such as square planar, tetrahedral, octahedral and so on. A strong covalent bond is formed only when the orbitals overlap to the maximum extent. The d-orbitals involved in the hybridisation may be either inner d-orbitals i.e. (n—l) d or outer d-orbitals i.e. nd. The complexes formed are called inner orbital complex (low spin complex) and outer orbital complex (high spin complex) respectively. Further, the complexes can be paramagnetic or diamagnetic in nature. The drawbacks of this theory are that this involves number of assumptions and also does not explain the colour of the complex.

Answer the following questions :

Section B

Question 4.

Which of the following acids represents Vitamin C?

[1 Marks]
  • (A) Benzoic acid
  • (B) Saccharic acid
  • (C) Gluconic acid
  • (D) Ascorbic acid
Question 5.

Rosenmund reduction is used for the preparation of Aldehydes. The catalyst used in this reaction is.

[1 Marks]
  • (A) Iron (II) oxide
  • (B) Pd-BaSO₄
  • (C) HgSO₄
  • (D) Anhydrous AlCl₃
Question 6.

Which alkyl halide from the given options will undergo SN1 reaction faster?

[1 Marks]
  • (A) (CH₃)₃C-Br
  • (B) CH₃-CH₂-Br
  • (C) (CH₃)₂CH-Br
  • (D) (CH₃)₃C-CH₂-Br
Question 7.

From the elements of 3d series given below, which element shows the maximum number of oxidation states?

[1 Marks]
  • (A) Manganese
  • (B) Titanium
  • (C) Scandium
  • (D) Chromium
Question 8.

Identify the tertiary amine from the following:

[1 Marks]
  • (A) CH₃–NH–CH₂–CH₃
  • (B) CH₃–CH(NH₂)–CH₃
  • (C) (C₂H₅)₂CHNH₂
  • (D) CH₃–N(CH₃)–CH₃
Question 9.

Nucleophilic addition of Grignard reagent to ketones followed by hydrolysis with dilute acids forms

[1 Marks]
  • (A) Tertiary alcohol
  • (B) Alkene
  • (C) Primary alcohol
  • (D) Secondary alcohol
Question 10.

In a given graph of zero order reaction, the slope and intercept are:

[1 Marks]
  • (A) Slope = k, Intercept = [R]₀
  • (B) Slope = k/2.303, Intercept = ln[R]₀
  • (C) Slope = -k/2.303, Intercept = n
  • (D) Slope = -k, Intercept = [R]₀
Question 11.

Assertion (A): p-nitrophenol is less acidic than phenol. Reason

(R): Nitro group is electron withdrawing and helps in the stabilization of p-nitrophenoxide ion.

[1 Marks]
  • (A) Assertion (A) is false, but Reason (R) is true.
  • (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  • (C) Assertion (A) is true, but Reason (R) is false.
  • (D) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
Question 12.

Assertion (A): Benzoic acid does not undergo Friedel–Crafts reaction. Reason

(R): Carboxyl group is deactivating and the catalyst aluminium chloride gets bonded to the carboxyl group.

[1 Marks]
  • (A) Assertion (A) is true, but Reason (R) is false.
  • (B) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  • (C) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  • (D) Assertion (A) is false, but Reason (R) is true.
Question 13.

Assertion (A): Fructose is a reducing sugar.

Reason (R): Fructose does not reduce Fehling solution and Tollen's reagent.

[1 Marks]
  • (A) Assertion (A) is false, but Reason (R) is true.
  • (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
  • (C) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
  • (D) Assertion (A) is true, but Reason (R) is false.
Question 14.

The general electronic configuration of d-block elements is :

[1 Marks]
  • (A) (n-1)d¹⁻¹⁰ ns¹⁻²
  • (B) (n-1)d¹⁰ ns² -³
  • (C) (n-1) d⁰ ns¹⁻²
  • (D) (n-1)d¹⁰ ns¹⁻²
Question 15.

Consider the following reaction :

[-1 Marks]
  • (A) A- Methanol, B -Potassium formate
  • (B) A- Ethanol, B -Potassium formate
  • (C) A- Methanol, B -Potassium acetate
  • (D) A- Methanol, B -Potassium Ethanol

Section C

Question 16. 18 g of a non-volatile solute is dissolved in 200 g of H₂O that freezes at 272.07 K. Calculate the molecular mass of the solute (Kf for water = 1.86 K kg mol⁻¹).
[2 Marks]

Paper Details

CBSE Board Exam 2024

Class

CLASS 12-PCM

Subject

CHEMISTRY

Year

2024

Set

Set 4

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