Motion Velocity

Rest and Motion

An object or a particle is said to be in the state of rest when it does not change its position with time with respect to the same reference point. Depending on the observer's position, rest can be absolute or relative.

An object is said to be in motion when it changes its position with time with respect to the same reference point. Motion can be linear, circular, oscillatory, or vibratory.

Types of Motion

Linear Motion: Motion along a straight line. Every particle of the body moves along parallel straight lines covering the same distance in the same time.

Circular Motion: Motion along a circular path. All particles move along concentric circles.

Oscillatory Motion: Back and forth motion about a fixed point in a definite interval of time. If the amplitude is very small, it is called vibratory motion.

Dimensional Motion

One-Dimensional Motion: Motion along a straight line or well-defined path.

Two-Dimensional Motion: Motion where two coordinates change with time.

Three-Dimensional Motion: Motion where all three coordinates change with time.

Distance and Displacement

Distance: Actual path length traversed by the body. It is a scalar quantity and always positive or zero. SI unit is metre.

Displacement: Shortest distance between initial and final positions in a particular direction. It is a vector quantity and can be positive, negative, or zero. Its magnitude is never greater than the distance.

Difference Between Distance and Displacement

Distance is the total path length traveled, scalar in nature, always positive or zero, and depends on the path taken. Displacement is the shortest path between two points, vector in nature, can be positive, negative, or zero, and independent of the path.

Instantaneous Velocity

The velocity of a body at a given instant of time when the velocity is variable. It is the derivative of displacement with respect to time.

Solved Examples

Example 1: A car moves along a straight road covering 100 m in 5 seconds. Calculate its average speed.

Solution: Distance = 100 m, Time = 5 s

Average speed = Distance / Time = 100 m / 5 s = 20 m/s

Example 2: A particle moves from point A to B, 50 m east, then to point C, 40 m west. Find the displacement.

Solution: Displacement = Final position - Initial position = 50 m east - 40 m west = 10 m east

Example 3: A body moves with uniform velocity of 10 m/s for 8 seconds. Find the distance covered.

Solution: Distance = Speed × Time = 10 m/s × 8 s = 80 m

Practice Set

• Level 1: Define rest and motion with examples.
• Level 2: Differentiate between distance and displacement with suitable examples.
• Level 3: A person walks 30 m north, then 40 m east. Calculate the total distance and displacement.

Answer Key

Level 1: Rest is when an object does not change position with time relative to a reference point; motion is when it changes position. Example: A book on a table is at rest; a moving car is in motion.

Level 2: Distance is total path length (scalar), displacement is shortest path with direction (vector). Example: Walking 5 m forward and 3 m back, distance = 8 m, displacement = 2 m forward.

Level 3: Total distance = 30 m + 40 m = 70 m. Displacement = √(30² + 40²) = 50 m northeast.

Uniformly Accelerated Motion

Acceleration and Types

Acceleration is the rate of change of velocity with time. It is a vector quantity with SI unit m/s².

Types of acceleration:

• Uniform acceleration: Velocity changes by equal amounts in equal time intervals.
• Variable acceleration: Velocity changes by unequal amounts in equal time intervals.
• Average acceleration: Total change in velocity divided by total time.
• Instantaneous acceleration: Acceleration at a specific instant, derivative of velocity with respect to time.

Equations of Motion

Let u = initial velocity, v = velocity after time t, a = acceleration, s = displacement, n = nth second.

For uniformly accelerated motion:

• v = u + at
• s = ut + ½ at²
• v² = u² + 2as
• sₙ = u + (a/2)(2n − 1)

For retarded motion (a negative acceleration):

• v = u − at
• s = ut − ½ at²
• v² = u² − 2as
• sₙ = u − (a/2)(2n − 1)

For free fall under gravity (a = g):

• v = u + gt
• h = ut + ½ gt²
• v² = u² + 2gh
• hₙ = u + (g/2)(2n − 1)

For upward motion against gravity (a = -g):

• v = u − gt
• h = ut − ½ gt²
• v² = u² − 2gh
• hₙ = u − (g/2)(2n − 1)

Maximum Height and Time

Maximum height attained: h_max = u² / (2g)

Time to reach maximum height: t = u / g

Total time for up and down: T = 2u / g

Initial velocity to reach height h: u = √(2gh)

Solved Examples

Example 1: A body starts from rest and accelerates uniformly at 5 m/s² for 4 seconds. Find the final velocity and distance covered.

Solution:

Given: u = 0, a = 5 m/s², t = 4 s

Final velocity, v = u + at = 0 + 5 × 4 = 20 m/s

Distance, s = ut + ½ at² = 0 + ½ × 5 × 16 = 40 m

Example 2: A body is thrown vertically upwards with velocity 20 m/s. Calculate the maximum height reached and time taken to reach it. (Take g = 10 m/s²)

Solution:

u = 20 m/s, g = 10 m/s²

Maximum height, h_max = u² / (2g) = 400 / 20 = 20 m

Time to reach max height, t = u / g = 20 / 10 = 2 s

Example 3: A car moving at 30 m/s applies brakes and comes to rest in 5 seconds. Find acceleration and distance covered during this time.

Solution:

u = 30 m/s, v = 0, t = 5 s

Acceleration, a = (v - u) / t = (0 - 30) / 5 = -6 m/s² (retardation)

Distance, s = ut + ½ at² = 30 × 5 + ½ × (-6) × 25 = 150 - 75 = 75 m

Practice Set

• Level 1: Define acceleration and state its SI unit.
• Level 2: A body accelerates uniformly from 10 m/s to 30 m/s in 5 seconds. Find acceleration and distance covered.
• Level 3: A ball is thrown vertically upwards with velocity 15 m/s. Calculate the time taken to reach maximum height and total time in air. (g = 10 m/s²)

Answer Key

Level 1: Acceleration is the rate of change of velocity with time. SI unit is meter per second squared (m/s²).

Level 2: u = 10 m/s, v = 30 m/s, t = 5 s

a = (v - u)/t = (30 - 10)/5 = 4 m/s²

s = ut + ½ at² = 10 × 5 + ½ × 4 × 25 = 50 + 50 = 100 m

Level 3: u = 15 m/s, g = 10 m/s²

Time to max height, t = u / g = 15 / 10 = 1.5 s

Total time in air, T = 2t = 3 s

Quick Reference Table

Common Mistakes and Misconceptions

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